0=9.54t-4.9t^2

Solution for 0=9.54t-4.9t^2 equation:

0=9.54t-4.9t^2

We move all terms to the left:

0-(9.54t-4.9t^2)=0

We add all the numbers together, and all the variables

-(9.54t-4.9t^2)=0

We get rid of parentheses

4.9t^2-9.54t=0

a = 4.9; b = -9.54; c = 0;
Δ = b2-4ac
Δ = -9.542-4·4.9·0
Δ = 91.0116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.54)-\sqrt{91.0116}}{2*4.9}=\frac{9.54-\sqrt{91.0116}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.54)+\sqrt{91.0116}}{2*4.9}=\frac{9.54+\sqrt{91.0116}}{9.8}
$